In a circle of radious 17 cm, two parallel chords are drawn on opposite side of a diameter The distance between the chords is 23 cm If the length of one chord is 16 cm, then the length of the other is (a) 34 cm (b) 15 cm (c) 23 cm (d) 30 cmIf y = sin^1 (2x/1x^2) sec^1 (1x^2/1x^2) 0 x 1, prove that dy/dx = If y = sin^1 (x/root 1x^2) cos^1 (1/root 1x^2) 0 x ∞, prove that dy/dx = cos1 (sin x) Differentiate the following with respect to x cot^1 (1x/1x) Differentiate the following with respect to xCOMEDK 08 If y = sin1 ((5x12 √1 x2/13)) , then (dy/dx) = (A) (3/√1 x2) (B) (12/√1 x2) (1/√1 x2) (D) (1/√1 x2) Check A

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Find dy/dx if y=sin^-1(2x/1 x^2)- dy/dx = (2x)/sqrt(1 x^4) siny = x^2 cosy(dy/dx) = 2x dy/dx = (2x)/cosy dy/dx = (2x)/sqrt(1 sin^2y) dy/dx=(2x)/sqrt(1(x^2)^2) dy/dx = (2x)/sqrt(1 x^4) Hopefully this helps!Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more




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2 Answers2 Active Oldest Votes 2 Note that ( sin − 1 x) ′ = 1 1 − x 2 then apply chain rule f ( g ( x)) ′ = f ′ ( g ( x)) g ′ ( x) = 2 ( 1 x 2) − 4 x 2 ( 1 x 2) 2 1 − find the derivative of f given by f x is equal to Sin inverse X assuming it exist Kindly solve the question Please answer this question if x = sin 3 t/ (cos 2t) 1/2 , y = cos 3 t/ (cos 2t) 1/2 , find dy/dx explain in great detail if y = (1 sin2x/1 sin 2x) 1/2 show that dy/dx sec 2 (π/4 – x) = 0 donot go shortcutSolution Solution y = sin − 1 (1 x 2 2 x ) ⇒ sin y = 1 x 2 2 x ⇒ cos y = 1 − sin 2 y = 1 − (1 x 2 2 x ) 2 = 1 x 2 1 − x 2 Differentiating it wrt x, cos y d x d y = (1 x 2) 2 2 (1 x 2) − 2 x (2 x) ⇒ cos y d x d y = (1 x 2) 2 2 (1 − x 2) ⇒ d x d y = cos y 1 ((1 x 2) 2 2 (1 − x 2) ) ⇒ d x d y = 1 − x 2 1 x 2 ∗ ((1 x 2) 2 2 (1 − x 2) ) ⇒ d x d y = 1 x 2 2
Dear Teachers, Students and Parents, We are presenting here a New Concept of Education, Easy way of selfStudy This is an AudioVisual e Guide, Find dy/dx for y=sin^1(1x^2/1x^2) 1118 Hewi is building a brick wall He needs 65 bricks for each row of the wallFind Dy Dx If Y Sin 1 2x 1 X 2 hviezdoslavov kubín 7 ročník hugolin gavlovic valaska skola mravov stodola if f x x 3 x 2 x 1 then f 2 humanizmus a renesancia znaky ii rákóczi ferenc portr
Y Sin 1 2x 1 X 2 Find Dy Dx čítanie pre prvákov online šalát z červenej kapusty s jablkom čo sa oplatí študova Ex 53, 14 Find 𝑑𝑦/𝑑𝑥 in, y = sin–1 (2𝑥 √(1−𝑥^2 )) , − 1/√2 < x < 1/√2 y = sin–1 (2𝑥 √(1−𝑥^2 )) Putting 𝑥 =𝑠𝑖𝑛𝜃 𝑦 = sin–1 (2 sin𝜃 √(1−〖𝑠𝑖𝑛〗^2 𝜃)) 𝑦 = sin–1 ( 2 sin θ √(〖𝑐𝑜𝑠〗^2 𝜃)) 𝑦 ="sin–1 " (〖"2 sin θ" 〗cos𝜃 ) 𝑦 = sin–1 (sin〖2 𝜃)〗 𝑦 = 2θIf y = (tan1 x) 2, prove that ( 1 x 2) 2 y 2 2x( 1 x 2)y 1 = 2 Explain in great detail If y = tan1 {




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This is the Answer of your question The answer is sin2x The picture has all the detailed steps and the formulas which are used to solve this problem Thank YouCalculus Find dy/dx y=sin (1/x) y = sin( 1 x) y = sin ( 1 x) Differentiate both sides of the equation d dx (y) = d dx (sin( 1 x)) d d x ( y) = d d x ( sin ( 1 x)) The derivative of y y with respect to x x is y' y ′ y' y ′ Differentiate the right side of the equation Tap for more stepsSee the answer See the answer See the answer done loading




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y = tan–1 (2 tan θ/ 1 tan2 θ) = tan–1 (tan 2θ) = 2θ = 2tan–1x differentiating wrto 'x' on both sides, we have (dy/dx) = 2 (d/dx) = tan−1 x = 2 (1/1 x2) ∴ (dy/dx) = (2/ 1 x2) Please log in or register to add a commentIf `y=sin^(1)((x^21)/(x^21))sec^(1)((x^21)/(x^21))` then `dy/dx` is equal to To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW If `y=sin^(1)((x^21So y = sin (2 sin 1 sin θ) = sin 2θ dy/dθ = 2cos 2θ dy/dx = (dy/dθ)/ (dx/dθ) = 2 cos 2θ/ cos θ = 2 (1 – 2 sin 2 θ)/√ (1 – sin 2 θ) = (2 – 4 x 2 )/√ (1 – x 2) Hence option (1) is the answer




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So,the 'y' in the question,arcsin(2x/1x^2) is a little difficult to handle,so a smart substitution has been done in the form of x=tan θ which simplifies the 'y' to be equal to 2 arctan(x) Now,y=2tan^1(x) Differentiating both sides,we get dy/dx=2*1/1x^2 as derivative of tan^1(x) is 1/1x^2 And dy/dx is what was asked in the question Cheers )Find dy/dx sin{1x2/1x2 Ask questions, doubts, problems and we will help youIf y=sin^(1)((2x)/(1x^2))sec^(1)((1x^2)/(1x^2)),\ \ 0




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find dy dx y sin 1 x2 1 x2 Mathematics TopperLearningcom 8s1l799 find dy dx y sin 1 x2 1 x2 Mathematics TopperLearningcom 8s1l799 Want to start a profitable Education Franchisee? Now how did I know that, becuase `dy/dx` is 3x 2 2, y must be the integral of 3x 2 2 `dy/dx` differentiation and integration are opposite processes Ok, so I just integrate this and I get `x^3/3`, and there is 3 on the front, so the 3 cancels out so I just get x 3 2x KFind `(dy)/(dx)` in the following`y=sin^(1)((2x)/(1x^2))` Haryana has released the HBSE class 10 Result 21 on 11 June 21 with 100% Pass Percentage




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4) We want to find dy/dx, which is on the LHS To get this dy/dx on its own we can multiply both sides by y So we get dy/dx = y log(2) 5) To finish this question we need to sub in for y and then we have an answer for dy/dx Recall y=2^x (from our original question) So we get dy/dx = (2^x)(log(2)) => our final solution If y = sin(2sin^1x), then dy/dx is equal to (A) (2 4x^2)/√(1 x^2) Sarthaks eConnect Largest Online Education Community If y = sin(2sin1x), then dy/dx is equal to (A) (2 4x2)/√(1 x2) (B) (2 4x2)/√(1 x2) (2 4x2)/√(1 x2) (D) (2 4x2)/√(1 x2) Login Remember RegisterIf y=cos^1(2xsqrt(1x^2)), find dy/dx Maharashtra State Board HSC Science (Electronics) 12th Board Exam Question Papers 164 Textbook Solutions Online Tests 60 Important Solutions 39 Question Bank Solutions Concept Notes & Videos 418 Time Tables 24 Syllabus




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Explanation We can use here the formula for derivative of sin−1x, which is d dx sin−1x = 1 √1 − x2 As such to find derivative dy dx for y = sin−12x using chain rule is given by dy dx = 1 √1 − (2x)2 × d dx (2x) = 2 √1 −4x2 Answer linkFree implicit derivative calculator implicit differentiation solver stepbystepFind dy/dx of ,y=1/sin (2x/1x^2) dy/dx =d sin (2x/1x^2)^1 /dx =1/sin^2 (2x/1x^2) d (2x/ 1x^2)/dx =1/sin^2 (2x/1x^2) (1x^2)d (2x)/dx 2xd (1x^2)/dx) / (1x^2)^2 =1/sin^2 (2x/1x^2) (1x^2)2 2x2x / (1x^2)^2 =1/sin^2 (2x/1




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